Question

Determine the force in each member of the truss shown by the method of joint.

20 kN 10 kN 3 m 20 kN 20 kN F С) E D 3 m 20 20 B A 3 m 3 m 3 m 3 m FIG. P4.27

Answer 1

20 leN oKN okN 3m 20kN 3m 20 3m VA 3 m 2 300 25 kN () 2 Fy 6 0 +20 +20 35 KN ) 2 MA VA x 6-H, » 6 -20a 3 20 2 HA 16HB 2 * 교5 kA

FAD 15 N 45 tan 2 Cas (20+e)5 2 Fy 20 Cas -२5 F Cos 45 F Cos 65° C-20) + 5 = o FCoS 450 + f Cos 25 о* CLmpre n) 47-7KAS FAC (Tension) FAD TA kng jont c C 2 Fen Fch FeD 20kN 20 Cos 45 FeD FcD -1५१५२ ५ (mprenry FeD 2

- 33. 5 68 kus (Cam presion В:- Takingjomt 450 453 2 O FC»S (20+0) p 35z coset Cs 2 F 0 F os Ces5 F Cos 25°: -25 J Solmg Cumpres on Fsp Temsi m) 20.67kN Ta kjomt F:- FEF ompresiom)

Falng Fr FG7 0 mpretrion -47.7 kA Conside BEqg = 3 E 3m 3 3m B LEF

Cenbidarn EFG LE 3V 3vi 544 Sn 27478 Smy & - 7o° t 2 45 Cmsider, jomt E Fores long Takeng FEG FEF EF Cas70" EG (Tensin)

jmt D Similary FAD 20 6 kw Creaion FDG 2