pooled proportion is 0.37 8
test statistic is 5.381
p value is 0.000
there is enough evidence to suggest that people under the age of 18 get into significantly more accidents.
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An insurance company selected samples of clients under 18 years of age and over 18 and...
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 Over Age of 18 n1 = 500 n2 = 600 Number of accidents = 180 Number of accidents = 150 We are interested in determining if the accident proportions differ between the two age groups. The p-value is:
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 Over Age of 18 n1 = 500 n2 = 600 Number of accidents = 180 Number of accidents = 150 We are interested in determining if the accident proportion for the Under 18 is larger than the proportion for Over 18. Let pu represent...
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 ni = 500 Number of accidents = 180 Over Age of 18 n2 = 600 Number of accidents = 150 We are interested in determining if the accident proportions differ between the two age groups. Refer to Exhibit 11-7. The p-value is a. 0.3...
Question 9 An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 ni = 500 Number of accidents = 180 SO-3 Over Age of 18 n2 = 600 Number of accidents = 150-36 Soo-.36 ISO - 3 180 360 .64 u 600 We are interested in determining if the accident proportions differ between the...
Records from previous years for a casualty insurance company show that its clients average a combined total of 1.7 auto accidents per day, with a standard deviation of 0.56. The actuaries of the company claim that the current standard deviation, o, of the number of accidents per day is not equal to 0.56. A random sample of 10 recent days had a mean of 2 accidents per day with a standard deviation of 0.26. If we assume that the number...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.09 hours, with a standard deviation of 2.29 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.31 hours, with a standard deviation of 1.65 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no...
Thi a previous pol, 29% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll..300 of 1096 adults with children under the age of 18 reported that their family to dinner together seven nights a week. Is there sufficient evidence that the aroportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased? Use...
In a previous poll, 36% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Suppose that, in a more recent poll, 378 of 1108 adults with children under the age of 18 reported that their family ate dinner together seven nights a week. Is there sufficient evidence that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased?...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.31 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mean dailyleisure time of 4.02 hours, with a standard deviation of 1.97 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children...
14. A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.23 hours, with a standard deviation of 2.25 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure difference in leisure time between adults with no children and adults with children (1-H2 H represent the adults with children under the age of 18 The e0% (Round...