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4.2.1 Sep Use the contingency table to complete parts a) through d) below Event A Event B Event Event D Event E a) Determine
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Answer #1

$Given from the table we get different event like $\\A\cap C=$ event A and event C both occur together$\\ $number of elements belong to $A\cap C=11\\ $number of elements belong to $A\cap D=9\\$number of elements belong to $A\cap E=10\\ $similarly others. Now total is given by=11+9+10+6+12+2=40 $\\P(A\cap C)=11/40=0.275\approx 0.28

P(A and C)=11/40=0.275 approximately .28

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