Question

Submission should follow the ET190 homework format. Ensure you show all work completety to receive full credit. Make sure all problems are done in using labels and appropriate units or subscripts. Box your final answer. 1. There are 5 capacitors with the value of 1500 pF. a. What is the total capacitance when they are all in series? -10 3e 1500 1500 1500 b. What is the total capacitance when they are all in parallel? Cr cie C Cs de 2. For the following two circuits determine the following: a. The CT of each circuit. b. The voltage between nodes A and B 10 pF 10pF SV 22pF 33p 10V 2| Page

Answer 1

4] The voltage across the capacitor is given by Vc, and the

RC = Time constant = 10k ohm x 0.002u F = 20us

V_s= supply voltage =20 v

Ve=V, *e RC

2 5 10 0.0000 Vc 18.09694 15.57642 12.13124 7.358352 4.463297 2.707267 1.642126 0.996051 40 50 60

Capacitor Voltage Vc 10 20 30 40 50 60 70 Time in us

4mH s200 2 2mH i ) Solving to Soling for L₂ and to in saree C22 a 125)=Lz+L5 = 2m + 2m1 2mH = 4H plmH 1 saling for L and L4 in Series 434) = L3 +Ls = 1H + IMH 4H 2mH bes L35 2H (1) Solving 23, and Los in parallel CO60 9 1.334m 41 leq = 1.334 mH (N) Solving for Total Inductance in series for Led and 4 L = Litleg z dnf + 1-334 mH [ 17 = 5.34 H

Of=10kHz (-0.0047pf Irons - ImA X = 2afc. 10 KHz Sv. 10.0097uf dr x 10000 X 0.004+ x106F XL z 3386.271 Impedance 2 =/ R? +(x, —x.)? XO, Reo Z. V Ex.)? - 8386.272 Vo = Ilmex Z = 3386.27_12 IMS Vs = | x10A x 3386.27 V = 3.38 V

000 1000 3. For RC Senior Greuit the time constant is given by T-RC R- Resistance c- capacitance (a) R=1002, C=1pF T= RxC = 100.12 TUF T: 100 or 1x10*s | 12.00 1.00 200 (b) R= 4.7k12, C = 0.019f DO 100 T= RxC = 4tkez x 0.01 F = 47x0x 0.01x1067 = 0.47 usor 4.7 x 10

B. For RL Series Ciaccits Pire constant is given by T= 1 L-inductomee R- Resistance [a] R-1022, L=100pH T= L P = 100H = lus loo a E = Jus or lots (b) R21.5Me, L3H T=L 3 3H 1.5 M22 .5 X 106 Te dus or 2x1065

- 11. Total inductance L. The inductance are in senes. BomH 9500 H L3 Ly=hit L₂ + L3 = 50ml + SOOH + O.OIMH = 50x103H+600x1064 +0.01 X1024 - 0.05 H or 50.5 MH RE 0.olm L2 O 50 MH L₂ and to are an senes :. L = 12 +L3 7. 50 H + 50mH Psomh GE2100 MH and now the Legand L LI 100 m 13 are in pauwkey 300 RODS a L -100mH 100 H 500 = 50mH TIL LOO NH 100M 4 08 Sunda