Question

Write a Java method called compare that takes two integers as input parameters and returns 1 if the first parameter is larger than the second parameter returns – 1 if the second parameter is larger than the first parameter, and returns 0 if the two parameters are equal.

Answer 1

Here is the code for the function asked.

Code:

public static int compare(int x,int y){

if(x>y)return 1;

else if(y>x) return -1;

else if(x==y) return 0;

return 0;

}

Sample Run:

you can see the output on the left side

ht Main.java @ saved 1 class Main { //compare that takes two integers as input parameters public static int compare(int x, int y){ //returns 1 if the first parameter is larger than the second parameter if(x>y) return 1; //returns – 1 if the second parameter is larger than the first parameter else if(y>x) return -1; //returns 0 if the two parameters are equal else if(x==y) return 0; return 0; //Using main just to test the compare function public static void main(String[] args) { System.out.println(compare(6,5)); System.out.println(compare(5,6)); System.out.println(compare(5,5)); 18 }