Question

Calculate the total amount of heat required to completely convert 500 g of ice at 0°C to liquid water at 50°C. (5 pts)
Aluminum (Al) - 23 x 10°C c, = 0.215 cal/g K = 900 J/kg.K L = 395 kJ/kg Copper a(Cu) - 17 x 10/°C c. = 0.0923 cal/g.K = 386 J
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50c W water {mcePT. mL mL & MCAT Cheat - mm 7 xro3 giren - 500 (L+ CAT] - 500 (133** 4187 (30-0)] - 3 542,350] 1000 1542, 3.

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