Question

gage learning Submitted An aqueous solution of potassium iodide has a concentration of 0.441 molal. The percent by mass of potassium iodide in the solution is Submit Answer Retry Entire Group 4 more group attempts remaining Crious Next Save and Est

Answer 1

by mass of - The objective is to be calculate the % potassium iodide in the solution is %. → Given Data : Het us assume that the mass of stront to be like m (Solvent) = 1 kg n s molarity * mass of solvent in kg where. n = no. of moles m . (0.231 mot lkg) * (1kg) = 0.231 mot Molar mass of KI , MM = 1 *MM(K) + 1 + MMC) 1*39.1 + 1 + 126.9 - 166 gimol mass Of kI 9 m = no. of mot et molar mass = 0.231 mol o 166 g/mol = 38.346 g.

90, mass of Solution - mass of Solvent + mass of ks 1000 9 + 38.3469 = 1038.346 9. mass % of ki a mass of km * 1001 mass of solutions 38.346 * 100 1038.346 = 3836 ( 1038.346 3.69 433 a 3.69 %