Question

In a classic carnival ride, patrons stand against the wall in a cylindrically shaped room. Once the room gets spinning fast enough, the floor drops from the bottom of the room! Friction between the walls of the room and the people on the ride make them the "stick" to the wall so they do not slide down. In one ride, the radius of the cylindrical room is R 6m and the room spins with a frequency of 23.2 revolutions per minute. What is the speed of a person "stuck" to the wall? m/s You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question What is the normal force of the wall on a rider of m-48 kg? N You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. What is the minimum coefficient of friction needed between the wall and the person? Sub You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. f a new person with mass 96 kg rides the ride, what minimum coefficient of friction between the wall and the person would be needed? You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. SWhich of the following changes would decrease the coefficient of friction needed for this ride? Oincreasing the rider's mass Cincreasing the radius of the ride Oincreasing the speed of the ride Oincreasing the acceleration due to gravity (taking the ride to another planet) You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. "To be safe, the engineers making the ride want to be sure the normal force does not exceed 1.7 times each persons weight - and therefore adjust the frequency of revolution accordingly. What is the minimum coefficient of friction now needed? Subm You currently bave 0 submissions for this auestion Only 10 submission

Answer 1

1] Speed in a circular motion = wr

= 23.2*2pi/60 *6

= 14.58 m/s

2] Normal on the wall, N = mv^2/r = 48*14.58^2/6 = 1700 N

3] minimum coefficient of friction = mg/N = 48*9.8/1700 = 0.277

4] It is same, as mass m gets cancelled out

u_s = 0.277