What is the molarity of a solution containing 15.2 g of KCl in 354 mL of solution?
Ans--- Given 15.2 g of KCl , first we have to calculate the moles of Kcl
we know molar mass of KCl=74.55
Therefore mole of Kcl = 15.2 g Kcl * 1mol kcl/74.55 g kcl
=0.203 moles of kcl
we know molarity = moles of solute / litters of solution
= 0.203/0.354
molarity =0.573 m
What is the molarity of a solution containing 15.2 g of KCl in 354 mL of...
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