What is the molarity(M) of a aqueous solution containing 22.5 g of sucrose(C12H22O11) in 35.5 mL of solution
What is the molarity(M) of a aqueous solution containing 22.5 g of sucrose(C12H22O11) in 35.5 mL of solution
First, calculate moles of sucrose
mol = mass / MW
MW of sucrose = 342.2965 g/mol
mol = (22.5)/(342.2965 ) = 0.065732 mol of sucrose
V of solution = 35.5 mL = 35.5*10^-3 L
so
M = mol/V = (0.065732)/(35.5*10^-3) = 1.8516 mol of sucrose per liter
What is the molarity(M) of a aqueous solution containing 22.5 g of sucrose(C12H22O11) in 35.5 mL...
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