An aqueous solution was made up by dissolving 34.5 g of sucrose, C12H22O11, in enough water to make 250 cm^3 of solution. The mass density of the resulting solution was 1040 kg/m^3. Calculate the molar concentration and molarity of sucrose in the solution.
Answer: 0,388 mol/kg
An aqueous solution was made up by dissolving 34.5 g of sucrose, C12H22O11, in enough water...
A solution is prepared by dissolving 50.2 g sucrose (C12H22O11) in 0.383 kg of water. The final volume of the solution is 355 mL. (Molarity=0.413, Molality=0.383, and percent by mass is 11.6%) For this solution, calculate mole fraction.
a solution is prepared by dissolving 50.4 g sucrose (c12H22O11) in 0.384 kg of water. The final volume of the solution is 355 mL. A. for this solution calculate molarity B. For this solution Calulate molality C. For this solution calculate percent by mass D. For this solution calculate mole fraction
A solution is made by dissolving 14 g of silver nitrate, AgNO3, in enough water to make exactly 250 mL of solution. Calculate the concentration (molarity) of AgNO3 in mol/L (M)
A) Calculate the molality of a sucrose solution made by dissolving 73.1 grams sucrose into 55.3 grams water. The molar mass of sucrose is 342.2 g/mol. Record your answer in scientific notation using 3 significant figures. Use * for the multiplication symbol. B) A sodium hydroxide solution that contains 55.5 grams of NaOH per L of solution has a density of 1.14 g/mL. Calculate the molality of the NaOH in this solution. Record your answer to 2 decimal spaces. C)...
A solution is made by dissolving 25.7 g of copper(II) chloride, CuCl2, in enough water to make exactly 100 mL of solution. Calculate the concentration (molarity) of CuCl2 in mol/L (M). M CuCl2
A.) An aqueous solution of sulfuric acid is made by dissolving 585.0 g of sulfuric acid in enough distilled water to make a one liter solution. Calculate the molarity, the molality, the mass% and the mole fraction of sulfuric acid in this solution. The density of this solution is 1.350 g/mL. MW H2SO4 = 98.00 g/mol. Please explain!! Thank you B.) Which substance(s) is (are) miscible in water? CH3CH2OH CI4 C6H6 CH3(CH2)13CH2OH CH3OH HOCH2CH2OH
A solution is made by dissolving 26.3 g of chromium(III) sulfate, Cr2(SO4)3, in enough water to make exactly 500 mL of solution. Calculate the concentration (molarity) of Cr2(SO4)3 in mol/L (M). M Cr2(SO4)3
2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150 mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? # of moles x 1000 Naot mass= 15,09 g molanty volume of source (m) Mol 40 g/mol voline...
(a) A solution is made by dissolving 3.00 mole of CaClas) in enough water to make solution. The density of the solution is 1.25 g ml? 4) Calculate the molality of the solution (not the molarity!) ugh water to make 2.00 L of [3 marks]
A solution is made by dissolving 5.61 g of a new polymer in enough water to make 260 mL of solution. At 25.0 oC, the osmotic pressure of the solution is 0.174 atm. What is the molar mass of the polymer in g/mol? (Use the E symbolism. e.g., 3123 would be 3.123E3 with 3 significant figures - i.e., 2 after the decimal point.)