Question

A marble rolls horizontally off a table with a speed of 3.7m/s. A second marble is dropped vertically from the table at the same instant. If the table is 1.20m high, (a) How far apart do the marbles land? (b) What difference is there in the times of impact of the two marbles?

Answer 1

et Vertical -0. The first meuble in the rells har antally table with spoed at 3.7 m's This implies, the marble has on intial spoed 37m/s 'twenda horizontal direction, ie, 339/56) component at velocity Now, to cover the height at 12m first marble, time taken is given by, 1:2 = ut + go ? Co velocity 1.2 = 4 xgt :) 12 = 10xt" the by hought isvered totally depende upon vertical component at Now, uvertical t 24 ID 0.19 by the ball Horizontal distance covered uhonzorded at 3.7 X049 during this time : 1.8m 04:37 m/s 12m 18 m

velocity > Now ball 2 has no horizontal simply falls vertically it is dropped bellow the point so it from which O 1.2m Tim taken bell 2 to reach the ground, 12= ut + fight by 2 Here also lo t: Fan J9283 - 0.495 1 (i) The balls are 18 m apart as inn be seen from the figure 12m .6 Bell 1 18 m Bell 2 11) The Both the marbles reach the ground at t= 0.4gs. * The difference in their time of impart is o.
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