Question

analyze the ir specteum of adipoyl chloride

16 apopodupe Transmittance 3500 35 75 3000 294341 2877.39 Wavenumbers (cm-1) 2000 1787.52 CTO 1455.10 1500 1402.73 1348.30 1277.01 123580 1940 11835 1989. 1000 $26.99 78501 720:43

Answer 1

Hi!

When analyzing IR spectra the most important thing is to understand what are this signals consequence of.

A signal will be detected for each different stretches of neighbor atoms. This technique is very important to determine functional groups.

In our particular molecule we have a very important group that is very clear on IR spectra that is the carbonyl. The Stretch is, for aliphatic ketones, 1715 cm-1. The shift happens in the spectra towards 1787 because of the -Cl, as you have already identified.

The C-Cl stretch is 850-550 cm-1. But it's not possible to determine exactly where it is.

Hope to have been helpful!