Question

The vapor pressure of water (H₂O) is 23.8 mm Hg at 25 °C. What is the vapor pressure of a solution consisting of 203 g of water and 0.213 mol of a nonvolatile nonelectrolyte?

VP(solution) = mm Hg

Answer 1

Given vapor pressure of water = 23.8 mm Hg nonj valite dectrolyte = 0.213 mol mass of water = 203 g Here solute = non volatile electrolyte solvent = water Apply Raoult�s law It staty that, the partial vapor of each component of liquids is equal the vapor pressure of the due component multiplied by is mole fraction in the mixture p_solution = p^0_solution X_solvent p_solution = vapor pressure of solution = ? p^0_solvent = vapor pressure of pure water = 23.8 mm Hg x_solvent = mole fraction of solvent x_solvent = loles of solvent/moles of solute + moles of solvent Given moles of solute (non volatile electrolyte) = 0.213 mol we need to calculate first moes of solvent (water) moles of solvent (water) = weight of water/molecular weight Given weight of water = 2039 moles of water = 2039/18 g/mol moles of water (solvent) = 11.28 mol molefraction of solvent