Question

Use RISA (or structural analysis program of your choice) to verify your solution from No. 2. a. Assume E = 200 GPA, A = 7000 mm b. Members are pin connected C. G is a pin (Ex and Fy restrained) d. A is a horizontal roller (Fx restrained) *Using the diagram below answer the question above. 2. Use method of joints to determine the force in each member of the truss. State if the members are in tension or compression. -2m- 2m- 5 kN SkN 5kN

Answer 1

5 KN Slepice Voing the method of Jornalog concepla (c) Consider the joint d':- O= Tan ( 32) = 56.310 TOE -) Fy=0; Tco 90 Toe sin ($6.310) = 5KN AT DE = 6 KN (T] =) G Too = 6008(56.3109 = 3.328 ~ 3.33 Klu - TED = 3.33 KN (CD) <=) Al Ċ : =) GFy=0) 1.5 TCE = 5 KN (T) 7 Tec =) Efn=o; TBC = Top = 3:33 KN (col TCD 5 KN = Abgante : TER O: Tañ( 49) = 387" To 0,= 0 - 36.87° TCE ITE

0.6 10 36.87 =. TBE C08 36.87 * TOE.CO8(36.870) -) Sify sos Teisin 36.87°+ Tas a in 36i87° - Toe sin 36.87€ 0.6 TFE +0.6 TBE = 0.6 Toe + 5 KW + TCE ob Ige + 0.6 78€ = (0.6*6) +5 = 8.61 Tee te Tee = 86 = 14.33 TEE + TBC = 14.33 KN 70 ) 512=0; Tre C08 36.87° - TRECO8 36.87 + 0.8 TFE - 0.8 TRE = 6*0.8 Tee - TBE = 6 *98 +6 @ From equations (1) 8625 TCETTE = 14.33 TEE -TBE = 6 2Tce = 2033 | The = 10.165KN ---☺ from equationg (2783) Ter = 14.33 -10.165 - 4.165 IN Toe = 4.165 Step 2 :- Al jou inlo ' :-) oztañ'() - 36.67° - ITMED TAR: 333+(4.465*0.8) Tag = 6.662 KNCCD) => [fy so = THE =(4,16540.62+5 = 4.499% 7.5 IN Es Tee = 7.5I6N(T) TBF TBE CO TBC AB 5 KN

TAF TBF =) Al- joint' F' :- O= Tań'(45) = 36.870 TGF To O = Tan (3/2) = 56.310 TAF INTEF => EFy=0; Taf sin 56.31° = The + Tee Sin(36.87°) 0.832 TAF = 7.5+(10.165*0.6) TAF = 16.345 KNP (c)] =) a Fr=o. Tana 16.345 608 56.31+(10.165*0.8) 1.1 Thee 17.198KN (T) 6) Aljoint ' :. T AGE TAF O= TGÓ (31272 56.310. An>$0 TAB =) Fy=0; TAG=TAR Sin (66.31% Ter= 16.34540-832 = 13.5998 a 13.6kN TAG TAG ² 13.6 KN (7)]