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also draw the sinusoid forms
2) Consider the following network in Fig (2). If the voltage source e has the waveform shown in Fig (1), answer the following
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piz C=2Mf CQ= lauf G&G are connect in parallel so we know Cer= Gtle C () f = 60 Hz Ceq=240 Cea = 12 uf 25 cut is 300 (eq = 12aurent division for capacity 1 - CL is Citle +170) (MA) 11 =18.83 Sin(lroat, 0.83 is 2 2+10 = 120 I is -1883 = 18.83 Sin ( 12

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