Question

Section 3 Bout A loop of wire sits in a uniform magnetic field, everywhere pointing toward you. Due to a changing magnetic flux through the loop, an induced current flows in the wire, clockwise as shown. The area of the loop is JO550 m, and the magnetic field initially has magnitude KO.410 T (a) Suppose that, over a time period of L..o0s, the magnetic field changes from its initial value, producing an average induced voltage of M, o.10 final value of the magnetic field after this time period? Answer: V. What is the T (b) Now let's set the magnetic field back to its starting magnitude of K.O.410 T. and assume we achieve the same induced voltage of M. b.10 period of LLOO s by keeping the magnetic field fixed but changing the area of the wire loop. What is the final value of the loop's area after this time period? Answer: Vover a time m2

please label each answer and write clearly

3 significant figures or correct power of 10 where applicable.

Answer 1

ven mac craular Looplaced in a that neh feld mag neh freld is passingper pen diel or Such auy the plane ot the toop to fluxtho ugh the do ap magneh The -कven by : .A NABIIATOSG majmet freld through the J०০৮ A rea vector of the doopdirected shere A = along the plane of leop angle between nozMal to the and A per bendicular the plane efsop Band both A Nouw, or normal) aure to EBIIAI cos o B Thus BA the Faradayls According to Ja of electro magmehc induchan, the nduced S म०n in the loop Caverage induced voltoze) BA dt

Thusmagnitude of avera e thduced emt is c(BA) eav Part la: ১e have, s freds area usng (, ear d BA)= A dB dB = change in magneh feld Bf: and initial value ot nagnehe final feld tme Bf, Be res pechvely interval tA CBf are given, we 6-10 V O 550 m 2 Oo9o T A- Be At o-SSO x Bf |० ५०० 0. 90 Bt IS. S3 0910 16-44 |6-५५ । Answer is

Patt b Nous magneh freld is fixed but area Loop changing, of BdA dBA) dt av dt dA Af- Ar final inital value of A resbect = At change in area Af, Ai = dt hme interval vely Given, Do 910T o A O-SSO m 2 Thu, e A-Ai AT O.910 XCA 1-400 400 X6 -10 B 6-10 A 0.S SO 9.38 Af 9-38 O-550 g-33 9.93 m2 Answer s

Part (c) Now A and are fixed is changing but angle 9 Such that BA CoS e ay BA Cose dt BA d (cose) BA (Cos - Cos At eav have, we 6-10 V Cay В O 910 T m2 - nital ange bétween B and A e Ot B and A final angle between 0910x 0.SSo (os 90- 0-550 X 1 6 10 O-9t0 X 2 S Ansiser i's 0.8 2 S