Question

2. Convert the bearings of the lines given in the table below (OA, OB, OC, and OD) to azimuths from north. Please note that all four lines have the common start points of 0. Also, compute the angle (smaller than 180°) between successive bearings. Show the work and draw a neat figure. Line Bearing Azimuth Angle OA N27°50'05"E AOB=? OB S38°12'44"E BOC=? OC S23°16'22"W COD=? OD N73°14'30"W DOA=?

Answer 1

13'M 30/ E 389glE 38 Rup S23 16/22 wO Azimi tial OA 27°S0 05 LAOB 1800-2P50'5- sa 12'4 = 11305 T OB Azimuth af OAB = 180- 38012 = R4T 16 Oc Aeimuth of oc = 180t 23° 16'22 = 2030 1622 /Boc = 38 12' tk +23 162 610296 COD = 1800-73 /430-230 1622 83 2q8 OD Azimath of oD 3609- 73/ 30 286° 45'301 | DOA = 13 14'30 + 27° 50'5 lo10 4135 NT 74 30

Anale Line Rearing Azimuth 11357 11" 610 29 61 OA 2T° 50'5E 270 S0'5 S38 12'4HE 14 kT(61 OB ৪3 2१'৪ OC S23 16' 22 W 203 16'221 1010 4 351 NT3 14/30/N 286 H5 30 OD