Question

Under which of the following conditions will a cell do the most work? (A) Q/K <...

Under which of the following conditions will a cell do the most work?

(A) Q/K < 1

(B) Q/K = 1

(C) E° < 0

(D) E° = 0

(E) Q/K > 1

The correct answer is A, but why ?
Thanks.

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Answer #1

answer : (A) Q/K < 1

from equilibrium concenpt .

1) Q < K the reaction is most favourable to forward direction. that means Q / K < 1

if K > 1 then \DeltaG is negative. this means that the cell working feasible

relation between \DeltaG and K

\DeltaG = - R T ln K

2) Q > K , the reaction is favourable to backward direction than means Q /K >1

3) Q =K , the reaction is exactly at equilibrium . here the cell stop working

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