18) How many grams of ammonium chloride are in 23.5 ml of a 0.887 M ammonium...

Question

Question

18) How many grams of ammonium chloride are in 23.5 ml of a 0.887 M ammonium chloride solution? Make sure to express in the c

Answer 1

Answer #1

Given that; volume of Ammonium chloride(NH4Cl)=23.5 ml= 23.5*10-3 litres

Molarity or Concentration of NH4Cl=[NH4Cl]=0.887 M

Number of moles= Molarity*volume(in litres)

So no of moles=0.887*23.5*10-3=2.08*10-2

Molecular weight of NH4Cl= 14+4+35.5=53.5 g/mol

Weight=no of moles*molecular weight

Weight=53.5*2.08*10-2 =1.11 g

Thus 1.11 grams of Ammonium chloride is required answer.

Answer 2

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