the z-scores that bound the middle 41% under the standard normal curve are z=-a and z=a. find the value of a
Given P(-a<z<a) = 0.41
To find a
from standard normal table P(z<0.54) = 0.7054
P(Z<-0.54) =0.2946
P(-0.54 < z< 0.54) = P(Z<0.54) - P(z<-0.54) = 0.7054-0.2946 = 0.4108 = 41%
Hence a = 0.54
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