Find the Z-scores that separate the middle 86% of the distribution from the area in the tails of the standard normal distribution.
Click the icon to view a table of areas under the normal curve.
The Z-scores are _______
P(|Z| < z) = 0.86
P(Z < z) = 0.86 + (1 - 0.86)/2 = 0.93
Take the value of Z corresponding to 0.93 from standard normal distribution table
1.48
The z scores are -1.48,1.48
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