The spaceship Enterprise 1 is moving directly away from earth at a velocity that an earth-based observer measures to be +0.69c. A sister ship, Enterprise 2, is ahead of Enterprise 1 and is also moving directly away from earth along the same line. The veolcity of Enterprise 2 relative to Enterprise 1 is +0.45c. What is the velocity of Enterprise 2, (in terms of c) as measured by the earth-based observer?
As we know that;
= v1(earth) = =0.69c
= v2( enterprise ) = -0.45
So,
= v2 (earth) = 0.69c - (-0.45c) = 1.14 c
The spaceship Enterprise 1 is moving directly away from earth at a velocity that an earth-based...
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suppose a spaceship heading directly away from the Earth at 0.75c can shoot a canister at 0.65c relative to the ship. Take the direction of motion towards Earth as positive. v1= 0.75 c v2= 0.65 c a) If the canister is shot directly at Earth, what is the ratio of its velocity, as measured on Earth, to the speed of light? (units for answer in mu/c=...) b) What about if it is shot directly away from the Earth (again, relative...
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Suppose a spaceship heading straight towards the Earth at 0.75c can shoot a canister at 0.55c relative to the ship. A) If the canister is shot directly at Earth, what is the ratio of its velocity, as measured on Earth, to the speed of light? B) What about if it is shot directly away from the Earth (again, relative to c)?
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