PLEASE show work! A small hole is drilled into the top of a solenoid, and an...
PLEASE helP! A solenoid has 600 turns per meter. Determine the magnitude of the magnetic field when a current of 0.35 A is present in the solenoid. Permittivity mu _o = 4 pi times 10^-7 T middot m/A. Solenoid magnetic field:____ (b) A 5000-turn toroid carries a current load equal 1.3 A. What should be its diameter to maintain an interior magnetic field of magnitude 30. Gauss (3.0 milli-Tesla)? Toroid diameter = ____
show work please. need help with this Question 3 (1 points) (#760978) (Ampere's Law} /(Solenoid) A solenoid with 25 turns per centimeter carries a current I. An electron moves within the solenoid in a circle that has a radius of 2.0 cm and is perpendicular to the axis of the solenoid. If the speed of the electron is 2.0 x 10 m/s, what is I?
1. A force of 5.78x10-16 N acts on an unknown particle that travels at a 90 ° angle through a magnetic field. the velocity of the particle is 5.65x104 m / s and the field is 3.20x10–2 T, how many elementary charges does the particle carry? 2.What potential must be applied to a source of mass ions (9.99x1027 kg) to be accelerated by a region where there is a 1.2 T perpendicular magnetic field, if the minimum electric field to...
please show full solution Si (a) Athin metallic ring with radius 15cm lies outside of an ideal solenoid (radius Sem) connected to a battery and a switch. The 10cm-long solenoid has 200tums. Explain your answers. (6) At the instant when the switch is suddenly closed, what would be the current direction in the ring? (a) After the switch has been closed for long time, the radius of the ring shrinks to 7cm. What is the current direction in the ring...
5.0. Protons with kinetic enerigy of 50 MeV are moving in the positive x direction and enter a magnetic B (0.5 T)k directed out of the plane of thepage ure extending from - 0 to -1 m as shown in 29.36. (a) Calculate the y compo nent of the protons momentum as they leave the magnetic field at m. (b) Find the angle a between the initial veloc- ity vector of the proton beam and the velocity vec tor after...
Finding the charge to mass (e/m) ratio of the electron Often in physics, we look for ways to find fundamental physical constants. From the set-up demonstrated in class, we are able to find a monumental combination of two physical constants-the charge of an electron (e) and the mass of an electron (m). Since the charge of an electron (e) is well known through other experiments, we will use the ratio of charge to mass to find the mass of an...
Finding the charge to mass (e/m) ratio of the electron Often in physics, we look for ways to find fundamental physical constants. From the set-up demonstrated in class, we are able to find a monumental combination of two physical constants-the charge of an electron (e) and the mass of an electron (m). Since the charge of an electron (e) is well known through other experiments, we will use the ratio of charge to mass to find the mass of an...
PLEASE SHOW ALL WORK 2 An electron (magnitude of its change is (q) = 1.6*109 Coulombs, and mass of an election me = 9.11x10² kg) enters a magnetic field of strength B= 2 x 10t Tesla, with a speed of 1.5*10%m/s perpendicularly and therefore moves in a circle. Calculate the radius of that circle.
please show work! part c as well please! im really struggling and on a time limit please help! 3. A proton = 1.60 x 10-19 C, moves through a uniform magnetic field into the page. The proton, moving at a speed of 2.0 x 10 m/s in the direction shown, feels a force of 3.0 x 10-15 N. a) What is the magnitude of the magnetic field? b) Draw a vector on the charge indicating the direction of the force...
PLEASE HELP ME AND SHOW STEPS. THANK YOU 1) It is desined to step up a vollage of 120 V to 96,000 v. The turns ratio N/N, of the transformer a) I/28 b) (64 x 10y )28 d) 8001 if the voltage is stepped that power is not lost in an ideal transformer, consider the situation in the above question. 2) Starting from the idea t up 800 times, the current is a) the same, since power is the same...