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5. The human resources department of a company found the average number of absences to be 2.2 per day. What is the probabilit
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Answer #1

5.

P(x absences in t days) = e^(-mean*t) * (mean*t)^x / (x!)

P(10 absences in 4 days) = e^(-2.2*4) * (2.2*4)^10 / (10!)

P(10 absences in 4 days) = 0.1157

(please UPVOTE)

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