the radioactive decay of CO-60 is a first order process the initial weight of the atom is 50 gram, after 260 days the remaining weight is 6.25 gram, what is the half-life if radiation atom
Find HL for CO-60
[A] = [A]0*(1/2)^(t/HL
6.25 = 50 * (1/2)^(260/HL)
Solve for HL
0.125 = (1/2)^(260/HL)
HL = 86.666 days
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