Question

Consider the window (of area 0.34 m2) of an airplane. If the pressure inside the plane is atmospheric pressure, while the pressure outside is 24 % of Patm, find the magnitude of the force on the window. Ignore the velocity of the airplane (i.e., ignore Bernoulli’s effect).

Answer 1

Pahn - ২42 ab ?am १oc) = २५ १atm - 2५ x?arm Patom | 6০ 16 १atm 100 १atm= |o138Sa 76x101325 100 \o132ऽ foet= 77007 Pa %3D fnet = Pock XA Poचेरु ल = 77007 X O-34 foel = 208৪-38 A

Answer 2

SOLUTION :

Inside pressure = 1 atmosphere = 101325 Pa

Outside pressure = 0.24 atmosphere = 101325 * 0.24 = 24318 Pa 

These pressures act in opposite directions.

So, net pressure on the window = 101325 - 24318 = 77007 Pa = 77007 N/m^2

So, 

force on the window 

= Net pressure  in N/m^2  * Area in m^2

= 770007 * 0.34  N

= 26182.38 N (ANSWER).