Question

Homework #1-Chapter1&2&4&5 (20pts for turned in on time) 7. (14pts)Carbon Dioxide Emissions. Burning fuels in power plants or motor vehicles emits carbon dioxide (CO2), which contributes to global warming. Table below shows CO2 emissions per person from countries with populations of at least 20 million. Carbon Dioxide emissions (metric tons per person) CO2 Country Ukraine SouthAfrica Italy Poland CO2 Country Country CO2 6.3 1.6 Ethiopia 0.1 Indonesia 7 1.8 Nepal Tanzania 0.1 Brazil 7.8 2 0.1 Egypt 7.8 Congo 2.6 0.2 Algeria Iraq 7.9 Spain United 8.8 Kingdom i l Korea,South Myanmar 0.2 2.9 Turkey tolomalt3 Bangladesh 0.3 9.3 Ghana 0.3 Korea,North 3.3 9.5 Kenya 0.3 Thailand 3.3 Japan Sudan 9.9 0.3 Argentina Mexico 3.6 Germany Nigeria Pakistan 10.8 0.4 3.7 Russia 13.8 0.8 China SaudiArabia 3.9 Philippines 0.9 17 Romania 4.2 Canada Peru Uzbekistan 18.4 4.2 Australia Vietnam 1 Venezuela 19.6 5.4 United States India 1.1 Malaysia 5.5 Colombia 1.3 Iran 6 Morocco 1.4 France 6.2 (3pts)Make a frequency histogram to display CO2 emissions per person. For the histogram, use classes' width of 2 metric tons/person and starting with 0 metric tons/person. (Hint, to a. produce a histogram, you will need to generate a frequency toble first, then draw bars continuously by the classes in the frequency table) Class Freq 0.0-1.9 e diw 2m ows s tolgms ( al anistnoo mta 1ol srs bns bns ESLD ublvibni yncm wolt ybut s ni ublvibsno msases nistnoo 2.0-3.9 sui 4.0-5.9 6.0-7.9 8.0-9.9 wol bad insbuuo (els) d bienoo d 1sin et adisb 10.0-11.9 12.0-13.9 noltudhib sd to 14.0-15.9 16.0-17.9 18.0-19.9 g 1aWets pd 91002 d tnobua B ont lo1ns oHlatos) zinabute y e ded 201ose ov b

Answer 1

First categorize the frequency from the co2 based on the class intervals.

Step1:

Step 2: Formula Step:

n P h M. Cumulative frequency Relative Frequency Lower boundaries Upper limits Upper boundaries Mid point Class Frequency Lower limit Frequency Histogram 2-38 0188 31 4-59 4 . 3553 4 5 65 o083 no8a 7 80 8-99 9 11 115 13 2 10 12 105 D042 10-119 1.43 14 125 8 4 12-139 DO00 1 14 14-159 135 15 14* 7.45 45 0021 19-13 9 13 Total 8 Class interva FE

Frequency Lower boundaries boundaries mulative frequency tive Frequency -F2/ SES1 5 -F3 / SFS 12 88 RE FND E2.113! EMDE2.1 FIND E2.1)-10 E3.1)-1-03-05 -02+05 03+05 RIGHT(E2,1)LEFTE2,1 )/2 RIGHTE3,1 ) LEFTIE3,1)/: MD(E3.1FIND MDE3.FIND-"E3,113) L2+F3 2-39 4-9 EMD(ES.1FND 8-99 10-116 E6,1-15- ob MD(END E113 MBEFND Lt+FE FLE+F? EFIGHTLE6,)+ LEFT(ES,1)|/2 - F6/ SF$ 12 MBLEFI MDEB1FIND 05 -05 =FS/&12 FE2/2 4-159 OTIE101 EETIE1021/2 MMD(E101 CIND E017-0c1-20 MDE1 1,1 FIND-E11,1 - G1 1-05 15-179 =MDE11.FND"E1 1,12 13) L10+F1 1 G11+05 RIGHTIF1 12) LEFTE112/2 F11/SF8 12 18-195 =SUME) E11) Total

Combination of bar chart as Class - Frequency and class - cumulative frequency , create histogram

Refer the above chart.