Question

Can I get detailed solution pls

If the size of a proton is of the order of 1 fm (10-15 m), what minimum kinetic energy must an electron beam have in order to “see” protons, inside a nucleus using electron scattering?

a. 10 MeV

b. 110 MeV

c. 1300 GeV

d. 1.2 GeV

e. none of the above

Answer 1

The formula of to calculate the energy is: E = hc/lambda E = 6.63 times 10^-34 times 3 times 10^8/1 times 10^-15 E = 19.8 times 10^-11 Joul E = 19.8 times 10^-11 times 6.24 times 10^9 GeV = E = 1.2 GeV

$E=\frac{hc}{\lambda }$

$E=\frac{6.63\times 10^{-34}\times 3\times 10^{8}}{1\times 10^{-15}}$
$E=19.8\times 10^{-11} Joul$ $E=19.8\times 10^{-11} \times 6.24\times 10^{9}GeV$

$\mathbf{E=1.2\; GeV}\; \; (Ans)$