Question

Question B4 Figure QB4 shows a spacecraft which is moving through space at a constant velocity. The xyz axes are fixed to the craft. At the instant under consideration, the craft has a constant rotation of 1 radis about the z axis, the solar panels are at an angle of 30° to the z axis and is increasing at the constant rate of radis. (a) Determine the vector expression of the angular acceleration of the right hand panel. (4 marks) (b) Name and determine the vector expression of each of the five terms on the right hand side of the relative acceleration equation aA = a +Axo + 2x(QxTwo) + 20 x V + Orel where a, is the acceleration of point A, a, is the acceleration of point O, A is the rate of change of S2, lao is the position of A relative to O, V is the velocity of A relative to O in the xyz frame and ac, is the acceleration of A relative to o in the xyz frame, (12 marks) (c) and hence determine the vector expression of the acceleration of point A. (2 marks) (d) In what direction is the arm holding the panel containing point A bent due to this motion? (2 marks)

Answer 1

Som with pannels Drawing given the Rough Diagram of satelile instant at Loire-sale aradis tu 20- Dostredis 0.6 m 17 Coloibos o 40.6sing 0-6m 2.4m) Q2 for Right Pannel there is no angulas artetelahion for Satellite pannel or But Radial acceleration for pannel exist. SO, Angular autleration for the pannel is in rector form. & panna = oitoh to ICSI Scanned with CamScanner

lel as draw all the Before solving paoblem o possible acceleration at point A. À E -12211 "Aroly k ozlo.6 sine î to.Gluso CS Scanned with CamScanner

bino. Ine acrelerahon pelor equation QA = 90* A* 840 + 12x (...*77) +2 1.x Vve + Qrel 3 + QA absolute acceleration of point A. 2) ao absoluele aceleration of point o. ão: oi toj tol 314 Ax tato = tangential accelerabon Of A with respoyo to À =2=o tas too done in post a ..Ax 8410 =0 4,3 D x( 12 x ry 40 ) Radial aceleration of point A about O, al is the summahön of Pedial aced) esanon of point about A about o and also of point A hands. pannel x (.2x rajo) 2? Imely S+ 0% (0.651no) * - &* o to 12 (4.4) ſ + 0.5" (0-6 singo) 5-0-540-6 60.87 20.095 ^ -0.1299 Â + 204 ġ dont (12 * Pero) 0.02sf +24, 0-075 î +2.4 ĵ -0.1299 Ê CamScanner

5) 2.2 x Vre! LI C0210i component of oceelelahon, V relative =0 22 X Voel = 0 5:) lart I translation al autlerabon (0) Melhor accelerahan for point A. GA 0,075 + 2.49 -0.1299 ☆ 11 Amei d) Asm holding point A bent due to the ponnel containing in Anti clockwise this motion when viewed viewed from foom the top. CS Scanned with CamScanner

I tried to show each component of acceleration by using basic of vectors. Here Velocity and acceleration of point A relative to origin is zero so the last two terms are zero.

Please forgive for any calculation mistake and do comment for any queries.

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