Question

Question 2 1 pts TOZA(cm) TAB(cm) 02 (rpm CW) 4.9 6.9 117 Determine the rotational speed (in rpm) of link 3 when link 4 (the slider) is in the limit position (and has O velocity) furthest away from the pivot O2? Provide your answer as a whole number in rpm.

Answer 1

solution : let's draw the mechanism when slidor is at farthest distance grom O. AB = 6.9 cm A = 4.9 cm = 11Typro . CW :=117 rpm tance = (49782. [-670 + sin 7oj] – (47) (17x A) –asto +sin 7e j] = 60-036 [-0.342 î+0.139] Toyo = -- 20-532 î +36-374. com/) 4 Ton = (AB). &z (6510 - sintoj Vo = 2.359 63 î–6-47183 (cm/s

To - Vo (wazi ft cineris) - VEA VA F 1.7 VBA = -1 → 2.3590, 9. – 6.41916=-(-20-532 +56-374) → 2.3598, î – 6-471 0; j = 20:5329–56-314 Compare 9-components. 2.35903 = 20.532 D og = 2.359 ég = 8.704 ( rpm) = 83-12 3pm Se és =. 83-12. Ypm CW / 20-532 = 8.704 rolls