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(1 point) Solve the following ODE subject to the initial condition y(0) = 3: V = 1² - 6² x² – 6² Also, calculate y(1/2). y =
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Answer #1

Cpfven diffeeen Hal equattan is y2 62 x2-62 ie. dy 4262 2-62 dy 262 d2 2르62 is in variable separable form This DE Integratingie y-6 CC-6) cy+6) C2+6)cy-6)clc x-6) (yt6 ) 4t6% -6y- 36) cy +eox-cley - css y +6y-61-36 y t64-62 -36 = cezt6at36-c30 clA The soleHon s 2 t62 +36- 12 Y = 2t6-12t2 8 +24 /3t +8 242+ 72 2x+24 24 (2+3) 2 C2t12) 12 Ca+3) 12 Treuired solution This i

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