Question

Please answer question 5.

(1) In a survey of self magazine readers, 41% said that they meditate. Assuming that this result holds true for the populatio ofall adults, find the probability that in a random ธample of 10 adults the number who meditate is - 1. exactly 3 none 3. exactly 7 4. at nost one 5. at least 9 6. Obtain the mean, variance and standard deviation.

Answer 1

5)

Let X denote the number of people that meditate. Then, $X\sim Bin(n=10,p=0.41)$

$P(X=x)=\binom{10}{x}(0.41)^{x}(1-0.41)^{10-x},x=0,1,2,...,10$

Required probability = $P(X\geq 9)=P(X=9)+P(x=10)=\binom{10}{9}(0.41)^{9}(1-0.41)^{10-9}+\binom{10}{10}(0.41)^{10}(1-0.41)^{10-10}=0.002066$