Question

Chapter 23, Problem 003 The cube in the figure has edge length 1.24 m and is oriented as shown in a region of uniform electric field. Find the electric flux through the right face if the electric field (a) is in the positive x direction and has magnitude 8.81 N/C, (b) is in the negative y direction and has magnitude 2.91 N/C, and (c) is in the xz plane, has x component -3.95 N/C, and has z component 4.73 N/C. (d) What is the total flux through the cube's surface for each field? (a) Number Units (b) Number Units (c) Number Units (d) Number Units Click if you would like to Show Work for this question: Open Show Work

Answer 1

Edge length of cube a = 1.24 m is face area A=a2 = {1:24) A = 1.54 m² Ã = 1.543 m (2734 7 = 8.Bli NIC (along positive x-direction) The electric flux through the right face PE - ZA'=(8.81 î).(1.549) = 0 [:2.9 =0] DE =0 N-mic (b) If Ě - 2.916-j) NIC = - 2.919 NIC Calong negative y direction) Now, electric flux, through the right face, de = É À=621913).(1.541) = -4.48 N-m/C. PE = -4.48 N-myc (C) 94 Ę in the xz-plane, then, A z = (-3.95 { + 4.73 Â ) N/c. .: + de = E. À = (-3.95 +4.732) •(1.543) = 0+0=0 → DE = 0 Nm'ye (@t) Total flex through the right face due to all fields 0=076-4.48) +0 - - 4.48 Nm/