Homework Answers
All the equations represent a double replacement reaction . Therefore the products would get formed by exchange of either positive ions or negative ions.
#5
Lead (II) acetate + Sodium Hydroxide solution
CME : Pb(C2H3O2)2 (aq) + 2 NaOH (aq) ----------------> Pb(OH)2 (s) + 2 NaC2H3O2 (aq) ...........[Using solubility rules, we can predict that Pb(OH)2 would be solid ]
To balance the equation, we add 2 before NaC2H3O2 and NaOH
CIE : for complete ionic equation, we will separate those substance which are in (aq) state
Pb+2 (aq) + 2 C2H3O2 -1 (aq) + 2 Na + (aq) + 2 OH - (aq) ----------> Pb(OH)2 (s) + 2 Na + (aq) + 2 C2H3O2 - (aq)
NIE : For net ionic equation, we will cancel out the common ions on both sides
Pb +2 (aq) + 2 OH- (aq) -------------------> Pb(OH)2 (s)
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#6
Lead (II) acetate + Aq. ammonia solution
Aq. ammonia solution is NH3 in water which can also be written as NH4OH
NH3 + H2O <------> NH4OH (aq)
CME : Pb(C2H3O2)2 (aq) + 2 NH4OH (aq) ----------------> Pb(OH)2 (s) + 2 NH4C2H3O2 (aq) ..........[Using solubility rules, we can predict that Pb(OH)2 would be solid ]
To balance the equation, we add 2 before NH4C2H3O2 and NH4OH
CIE : for complete ionic equation, we will separate those substance which are in (aq) state
Pb+2 (aq) + 2 C2H3O2-1 (aq) + 2 NH4+ (aq) + 2 OH - (aq) -------> Pb(OH)2 (s) + 2 NH4+ (aq) + 2 C2H3O2 - (aq)
NIE : For net ionic equation, we will cancel out the common ions on both sides
Pb+2 (aq) + 2 OH - (aq) --------> Pb(OH)2 (s)
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#7
Cobalt (II) nitrate solution + Sodium carbonate solution
CME : Co(NO3)2 (aq) + Na2CO3 (aq) ----------------> CoCO3 (s) + 2 NaNO3(aq) ........[Using solubility rules, we can predict that CoCO3 would be solid ]
To balance the equation, we add 2 before NaNO3
CIE : for complete ionic equation, we will separate those substance which are in (aq) state
Co +2 (aq) + 2 NO3 - (aq) + 2 Na + (aq) + CO3 -2 (aq) ----------------> CoCO3 (s) + 2 Na + (aq) + 2 NO3 - (aq)
NIE : For net ionic equation, we will cancel out the common ions on both sides
Co +2 (aq) + CO3-2(aq) ----------------> CoCO3 (s)
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#8
Cobalt (II) nitrate solution + Sulfuric acid solution
CME : Co(NO3)2 (aq) + H2SO4 (aq) ----------------> CoSO4 (s) + 2 HNO3(aq) ........[Using solubility rules, we can predict that CoSO4 would be solid ]
To balance the equation, we add 2 before HNO3
CIE : for complete ionic equation, we will separate those substance which are in (aq) state
Co +2 (aq) + 2 NO3 - (aq) + 2 H + (aq) + SO4 -2 (aq) ----------------> CoSO4 (s) + 2 Na + (aq) + 2 NO3 - (aq)
NIE : For net ionic equation, we will cancel out the common ions on both sides
Co +2 (aq) + SO4 -2(aq) ----------------> CoSO4 (s)
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#9
Cobalt (II) nitrate solution + Aq. ammonia solution.
As described earlier, aq. ammonia is NH4OH (aq)
CME : Co(NO3)2 (aq) + 2 NH4OH (aq) ----------------> Co(OH)2 (s) + 2 NH4NO3(aq) .......[Using solubility rules, we can predict that Co(OH)2 would be solid ]
To balance above equation, we add 2 before NH4OH and NH4NO3
CIE : for complete ionic equation, we will separate those substance which are in (aq) state
Co +2 (aq) + 2 NO3 - (aq) + 2 NH4+ (aq) + 2 OH - (aq) ---------> Co(OH)2 (s) + 2 NH4+ (aq) + 2 NO3 - (aq)
NIE : For net ionic equation, we will cancel out the common ions on both sides
Co +2 (aq) + 2 OH - (aq) --------------> Co(OH)2 (s)
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#10
Ammonium acetate solution + Sodium hydroxide solution
In this reaction NH4OH is formed as one of the products . NH4OH is very unstable and dissociates into NH3 gas and water . The reaction is written below.
CME : NH4C2H3O2 (aq) + NaOH (aq) --------------> NH3 (g) + H2O (l) + NaC2H3O2 (aq)
CIE : for complete ionic equation, we will separate those substance which are in (aq) state
NH4 + (aq) + C2H3O2 - (aq) + Na + (aq) + OH - (aq) --------> NH3(g) + H2O (l) + Na + (aq) C2H3O2 - (aq)
NIE : For net ionic equation, we will cancel out the common ions on both sides
NH4 +(aq) + OH -(aq) --------> NH3(g) + H2O (l)
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An aqueous solution of sodium sulfate is reacted with an aqueous solution of lead(II) nitrate. a. Write out the balanced reaction when sodium sulfate is reacted with lead(II) nitrate. Include ph. b. What is the precipitate in the above reaction? 2. A forensic scientist wishes to identify an unknown salt powder discovered at a crime scene. She has reas to believe the sample is either cesium chloride, lithium acetate or aluminum perchlorate. She chooses to identify it by reacting with...
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