Question

Force X has a magnitude of 3 pounds, and Force Y has a magnitude of 10 pounds. They act on a single point at an angle of 60° to each other. Answer the following questions. Treat Force X as a horizontal force with Force Y acting above it and pointing into Quad I What is the magnitude of the resulting force? pounds (Do not round until the final answer. Then round to one decimal place as needed.) What is the directional angle of the resultant force? nº (Do not round until the final answer. Then round to one decimal place as needed.)

Answer 1

TK 60° ya let ox' and oy' be the horizontal and vertical axes of system. x acts with magnitude 3 pounds directly to the → X' Ox direction y acts with magnitude 10 pounds to the oy direction : The force y can be resolved into two components y cos 600 and y sin 60° along OXand oy' direction respeetively Then, resulent force along on direction is Rx = X+YCOs 609 = 3+10 COJ 60 = 3+5 = 8,

and along oy direction is Ry = y sin 60° = 10 x 10 x 2 = 543 Magnitude of resultant force = √ RM + Ry 89+(533) C = 64+75 = 111:8) pounds and the directional angle = tan' ( RY) tan' ( SVE 8 E 47:3