Question

BAC for 165lb male who claims that over a 4 hour period he drank four 12-ounce bottles of beer which had an alcohol content of 5% and one 1.25-ounce shot of vodka which was 100-proof.

How to work through the equation:

BAC =TAR

Where BAC = blood alcohol concentration in g/L

                   A= weight of pure ethanol consumed in grams

                   W= weight of individual in Kilograms

                    R= Widmark’s rho factor for man (0.68) or woman (0.55), units are L/Kg

                   H= drinking period in hours

                 = Widmark’s beta factor, ethanol elimination rate for humans in g/L/hr (average is 0.15)

Conversions that might be needed:

1fl oz water= 29.56 g

1fl oz pure ethanol = 23.3g

Answer 1

Where, BAC = blood alcohol concentration in g / L A-weight of pure ethanol consumed in grans-(12 ounce 590 alcohol- W- weight of individual in Kilogrns 165lb 165x 0.453 74.842 kg R Widmak srho factor for man (0.68) units are L Kg H-dinking period in hous 4 hr p- Widmark'sbeta factor, ethanol elimination rate for humans ing /LIhr (average is 0.15) 1fl oz pure ethanol 23.3g BAC- 12x 23.3x 5 100 -13.98 g H1.25 once of 100% vodka-1.25x 233-29. 125-43105g (43.105 g) (74.84 Kg)x(0.68L Kg) (43, 105 8-(06g L) -(0.15 g/LIhrx4 h) BAC : ( 50.89 L) BAC 0.8469-0.6g L 0.246g L BAC-0.246 g /L