Question

The BAC is usually expressed as a percent based on weight/volume. This means that the BAC is the grams (g) of alcohol present
1. the amount of alcohol ingested 2. an estimate of the individuals water volume 3. Use the following equation: g of ethanol
II. Calculate the volume of water in the mans body A. Convert pounds to kg. Use the tables from chapter 1 B. Convert kg to m
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Answer #1

1).No. of Beer consumed = 4

1beer = 12 fluid ounces

Total beer consumed = 4 × 12 fluid ounces = 48 fluid ounces

As beer has 5 vol% alcohol

Alcohol consumed = 0.05 × 48 fluid ounces = 2.4 fluid ounces

1 fluid ounce = 29.6 mL

Alcohol consumed = 2.4 × 29.6 mL = 71.04 mL

Density of alcohol = 0.79 g/mL

Alcohol consumed = 71.04 × 0.79 g = 56.1216 g

2). Weight of man = 160 lb = 160 lb × 0.453 kg/lb = 72 48 kg

(As 1lb = 0.453 kg)

Volume of man's body = 72.48 kg × 1000 mL/kg = 72480 mL

Volume of water in man's body = 0.68 × 72480 mL = 49286.4 mL

3). BAC = (g of ethanol consumed)/ (volume of water in man's body in mL) = 56.1216 g / 49286.4 mL = 0.0011387 = 0.11387 %

4). As 1 dL = 100 mL

So, 49286.4 mL = 492.864 dL

BAC = 56.1216 g/ 492.864 dL = 0.11387 g/dL

5). The legal definition of intoxication has BAC = 0.08%

As BAC in person = 0.11387%, this means the person is intoxicated as amount found is greater than as per legal definition.

6). Metabolism for ethanol in body takes place in liver. The ethanol is first converted into aldehyde by alcohol dehydrogenase with peroxisomes and microsomes which is then converted into acetate by aldehyde dehydrogenase with mitochondria.

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