A square loop 10 cm on a side consists of 100 turns of wire that experiences...
A square loop 10 cm on a side consists of 100 turns of wire that experiences a minimum torque of zero and a maximum torque of 0.045 Nm. If the current in the loop is 2.82 A, calculate the magnetic field strength that the loop rests in
Homework Answers
Area
A=S^2=0.1^2=0.01 m^2
Maximum torque
Tmax=NIAB
=>B=Tmax/NIA
B=0.045/100*2.82*0.01
B=0.01596 T or 15.96 mT
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