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An object is launched with an initial velocity of
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Answer #1

Sol 26,T 36.9 2 976m ) 4S 76m 2) 40.44 m (3)20 m

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Answer #2

SOLUTION :



Part A 



Horizontal component of velocity

= 50 cos(36.9)

= 39.9842 m/s



So,



x-value at time t = 39.9842 t meters.



So, 



X-VALUES TABLE :



t            x-values (meters)



0                   0


1                 39.984


2                 79.968


3                119.953


4                159.937


5                199.921


6                239.905




So , x -values =  { 0, 39.984, 79.968, 119.953, 159.937, 199.921, 239.905 } (ANSWER).




Part B 



Vertical component of velocity

= 50 sin(36.9)

= 30.021 m/s



So,



y-value at time t = u t - 0.5 g t^2  (meters)



So, 



Y-VALUES TABLE :



t            y-values (meters)



0                   0


1                 25.121


2                 40.442


3                 45.963


4                 41.684


5                 27.605


6                  3.726



So , y -values =  { 0, 25.121, 40.442, 45.963, 41.684, 27.605, 3.726 } (ANSWER)

answered by: Tulsiram Garg
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