Calculate the current which must pass through an ideal solenoid so that in its interior a magnetic field of 200 mT is generated. The solenoid has 800 turns (loops) of a wire of radius 4.0 cm.
we know that
B = (u_o x N x I/2pi x a)
or I = (B x 2pi x a/u_o x N)
where I is current,B = 200 mT = 200 x 10^-3 T,a = 4.0 cm = 4.0 x 10^-2 m,u_o = 4pi x 10^-7 T.m/A and N = 800 turns
Calculate the current which must pass through an ideal solenoid so that in its interior a...
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