c. Calculate the molarity of the solution made by pipetting 5 mL of 2.00 + 0.02 M NaOH with a volumetric pipet and transferring this to a 100 mL volumetric flask and diluting to the mark. Show the equation used to calculate error
c. Calculate the molarity of the solution made by pipetting 5 mL of 2.00 + 0.02...
What is the final concentration of a solution prepared by pipetting 10.00 mL of a 0.1284 M NaOH into a 25.00 mL volumetric flask and diluting with water to the mark?
A pipet is used to transfer 10.00 mL of a 4.00 M stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 1.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
A stock solution was prepared by dissolving 0.593 g of pure ASA (molar mass = 180.2 g/mol) with NaOH solution and diluting with water in a 1000 mL volumetric flask. This was followed by pipetting 4.00 mL of the stock solution into flask A and 5.0 mL of the stock into flask B. Flasks A and B were each diluted to 20 mL mark of the volumetric flask. What are the concentrations, in molarity, of ASA in flasks A and...
calculate the molarity of the new solution 5. You prepare a stock solution of cupric sulfate pentahydrate by adding 3.745 g to a volumetric flask and filling the flask to the 100.0 mL mark with water. You then add 3.00 mL of the stock solution and 2.00 mL of water to a test tube and mix well. Calculate the molarity of the new solution. a. 0.225 moles b. 0.150 moles C. 0.100 moles d. 0.352 moles e. 0.0900 moles
The molarity of a solution prepared by diluting 2.67 g of NaOH to 100.0 mL in a volumetric flask is
The molarity of a solution prepared by diluting 2.67 g of NaOH to 100.0 mL in a volumetric flask is?
A stock solution of Cu2+(aq) was prepared by placing 0.9157 g of solid Cu(NO3)2∙2.5 H2O in a 100.0-mL volumetric flask and diluting to the mark with water. A standard solution was then prepared by transferring 2.00 mL of the stock solution to a second 25.00-mL volumetric flask and diluting to the mark. What is the concentration (in M) of Cu2+(aq)in the stock solution? What is the concentration (in M) of Cu2+(aq)in the standard solution?
Start with a 1230.0 ppm Stock Zn solution. Prepare control 1 by diluting 2.00 mL of Stock Zn solution in a 200.0 mL volumetric flask and dilute to the mark. Prepare control 2 by diluting 2.00 mL of control 1 into a 100.0 mL volumetric flask. What is the Zn concentration (ppm Zn) in control 2? Report your answer to 4 decimal place.
2. Calculate the molarity of a solution made from 15.00 mL of 32.0 wt. % HCl stock (density of 1.161 g/mL) diluted to 100 mL in a volumetric flask. Calculate the spike volume of that 100 mL dilute solution needed to make 1.000 L of 1.25 x 10 ppm HCl solution.
5.00 mL of a solution containing a monoprotic acid was placed in a 100-mL volumetric flask, diluted to the mark with deionized water and mixed well. Then, 25.00 mL of this diluted acid solution was titrated with 0.08765 M NaOH. 9.23 mL of NaOH was required to reach the endpoint. a. What does the term monoprotic mean? b. Determine the molar ratio between the acid and NaOH. c. Calculate the moles of NaOH used in this titration. d. Calculate the...