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A4: A refrigerator door has a height and width of H = 1 m and W = 0.65 m, respectively, and is situated in a large room for w
door consists of a layer of polystyrene insulation (k = 0.03 W/m $ K) sandwiched between thin sheets of steel (E = 0.6) and p

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Son Given that - HIMA = 1X0.65 W = 0.65 m A = 065m2 K = 0.03 W/m ok Two = Tsus = 25 = 298 K Ts, - 5°C = 298k &= 0.6 So from tNun = 5 0.825 + 0-381|2.19X10JY [1+LD1492 Judaler Nun = 156.6 Also find 20.92x10 6 x 14.82 X10-6 Rayleigh numer - Rom- g B ToAlso from egn.o - 2.0 - 4 X 0.651298 - 298 + 0.625.67X168 x0.65 x/1998(278)4] 9w.o=152 +42.80) 190,0 = 94.30 w AS we have to

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