current = JA or
dI = J dA
dI = Br 2?r dr
integrate, with r = 1.30 mm to 1.310 mm
I = 2B? ? r2dr = (1/3) 2B? r3 =
(1/2) * 2 * 2.34 x105 * ? * (1.3103 - 1.303 ) x10-9 =
37.56 x10-6 amps = 37.56 ?A
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