Question

Capacitor Circuits I Each of the circuits below cesists of baery and several capaciors Several of the voltapes, charges and capacitances are indicated Use conservation of charpe and the detinition of capaciance to determine as many of the other voltages, charges, and capacitances as possible B 24 6 HC 12V 12 V 12 uC 30 V 18 uC CI E 14 C esa Conmanity Colkgs, Mex AZ 85202 Page 3.6 and Trevor F. Meder

Answer 1

capacitors D and E are connected in series so charge will be same on both. that is charge on the capacitor E is q_E = 18muc. potential difference across the capacitor D is Q = Cv 18 = 2 times V V = 9 volt Than the voltage across the capacitor E is VE = 3volt than the capacitance of the capacitor E is CE = q_E/VE = 18/3 C_E = 6 muF B and C are connected in series so charge will be same on both. That is charge on capacitor C is q_c = 16muc potential difference across B is V_B = Q_B/C_B = 16muc/2muF VB = 8 volt than voltage across the capacitor C is Vc = 4volt than capacitance of the capacitor C is C_c = q_c/Vc = 16/4 C_c = 4 muF Voltage across the capacitor A is V_A = 12volt than charge on A q_A = 1 times 12 q_A = 12muc A and B are connected in series so charge will be same on both charge on capacitor A is q_A = 12muc C and D are connected in parallel so voltage across both will be same. V_D = V_C.