Question

Draw a Free Body Diagram of the point representing the weight as a force pulling down, and the two cables AC and BC as tension forces pulling away from the point Develop the trigonometric forces for the x and y components for AC, A, BC, and BCy and list them with a negative sign where appropriate. Assume positive is to the right and positive is up Chose the correct trigonometric break down for these cables ACX - AC cos 45" Acy. AC sin 45 BCX -- BC cos 30* BCy -- BC sin 30" ACX - AC cos 45"

Answer 1

A Bc6230- 7 W = BC Sinzo + AC Sin 45° AC (345º = BC 6530 Besin 30 te x BC Alx = - AC 66545° Bcq: BC 4330 45° ...> - Aly = AC sin 45° | Bey = Be Sin 30° 117 W= 2 kN (AC) max (Be)max = 1.9 KN W = 1.9 (sin 30 + Sin 45°) = 1.9 (+ 3) = 2.595 > 2 KN . The system will fail.