I don't know how to terminate the code in the second time that whether or not...
I don't know how to terminate the code in the second time that whether or not the users want to continue to get a new number. PLEASE HELP.
To make telephone numbers easier to remember, some companies use letters to show their telephone number. For example, using letters, the telephone number 438-5626 can be shown as GET LOAN.
In some cases, to make a telephone number meaningful, companies might use more than seven letters. For example, 225-5466 can be displayed as CALL HOME, which uses eight letters.
Write a program that prompts the user to enter a telephone number expressed in letters and outputs the corresponding telephone number in digits.
If the user enters more than seven letters, then process only the first seven letters.
Also output the - (hyphen) after the third digit.
Allow the user to use both uppercase and lowercase letters as well as spaces between words.
Moreover, your program should process as many telephone numbers as the user wants.
The below is my code
#include
#include
#include
using namespace std;
int main() {
char starter;
string inputLetters;
int count = 0;
cout << "Enter Y/y to convert a telephone number from letters to digits." << endl;
cout << "Enter any other letter to terminate the program." << endl;
cin >> starter;
while(starter == 'y' || starter == 'Y')
{
cout << "Enter a telephone number using letters: " << endl;
getline(cin,inputLetters);
cout << endl;
int i = 0;
while (i
{
bool notSpace = true;
switch (inputLetters[i])
{
case 'A':
case 'a':
case 'B':
case 'b':
case 'C':
case 'c':
cout << "2";
count++;
break;
case 'D':
case 'd':
case 'E':
case 'e':
case 'F':
case 'f':
cout << "3";
count++;
break;
case 'G':
case 'g':
case 'H':
case 'h':
case 'I':
case 'i':
cout << "4";
count++;
break;
case 'J':
case 'j':
case 'K':
case 'k':
case 'L':
case 'l':
cout << "5";
count++;
break;
case 'M':
case 'm':
case 'N':
case 'n':
case 'O':
case 'o':
cout << "6";
count++;
break;
case 'P':
case 'p':
case 'Q':
case 'q':
case 'R':
case 'r':
case 'S':
case 's':
cout << "7";
count++;
break;
case 'T':
case 't':
case 'U':
case 'u':
case 'V':
case 'v':
cout << "8";
count++;
break;
case 'W':
case 'w':
case 'X':
case 'x':
case 'Y':
case 'y':
case 'Z':
case 'z':
cout << "9";
count++;
break;
case ' ':
notSpace = false;
break;
default:
cout << "Invalid input.";
}
if (count == 3 && notSpace)
cout << "-";
if (count == 7)
break;
i++;
cout << endl;
}
cout << "To process another telephone number, enter Y/y";
cout << "Enter any other letter to terminate the program.";
cin >> starter;
cout << endl;
count = 0;
}
//system("pause");
return 0;
}
Homework Answers
The modified lines are explained with comments
Modified program
#include<iostream>
#include <cstring>
#include<limits>
using namespace std;
int main() {
char starter;
string inputLetters;
int count = 0;
cout << "Enter Y/y to convert a telephone number from letters to digits." << endl;
cout << "Enter any other letter to terminate the program." << endl;
cin >> starter;
while(starter == 'y' || starter == 'Y')
{
cout << "Enter a telephone
number using letters: "<<endl;
// to avoid taking empty string
from get line because of new line
cin.ignore(
numeric_limits<streamsize>::max(), '\n' );
getline(cin,inputLetters);
int i = 0;
while (i<8)
{
bool notSpace = true;
switch (inputLetters[i])
{
case 'A':
case 'a':
case 'B':
case 'b':
case 'C':
case 'c':
cout << "2";
count++;
break;
case 'D':
case 'd':
case 'E':
case 'e':
case 'F':
case 'f':
cout << "3";
count++;
break;
case 'G':
case 'g':
case 'H':
case 'h':
case 'I':
case 'i':
cout << "4";
count++;
break;
case 'J':
case 'j':
case 'K':
case 'k':
case 'L':
case 'l':
cout << "5";
count++;
break;
case 'M':
case 'm':
case 'N':
case 'n':
case 'O':
case 'o':
cout << "6";
count++;
break;
case 'P':
case 'p':
case 'Q':
case 'q':
case 'R':
case 'r':
case 'S':
case 's':
cout << "7";
count++;
break;
case 'T':
case 't':
case 'U':
case 'u':
case 'V':
case 'v':
cout << "8";
count++;
break;
case 'W':
case 'w':
case 'X':
case 'x':
case 'Y':
case 'y':
case 'Z':
case 'z':
cout << "9";
count++;
break;
case ' ':
notSpace = false;
break;
default:
cout << "Invalid input.";
}
if (count == 3 && notSpace)
cout << "-";
if (count == 7)
break;
i++;
// print
empty string to print the digits continuously not line by
line
cout <<
"";
}
// print new line
cout<<"\n";
cout << "To process another telephone number, enter Y/y\n";
cout << "Enter any other letter to terminate the program.\n";
cin >> starter;
cout << endl;
count = 0;
}
//system("pause");
return 0;
}
Sample Input/Output
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