Suppose a straight 1.25 mm -diameter copper wire could just "float" horizontally in air because of the force due to the Earth's magnetic field B⃗ , which is horizontal, perpendicular to the wire, and of magnitude 6.4×10−5 T .
Part A
What current would the wire carry?
Express your answer using two significant figures.
Part B
Does the answer seem feasible?
Does the answer seem feasible?
yes | |
no |
as per equilibrium of forces
mg = B i L
density * volume * g = B i L
8.96* 10^3* 3.14* (1.25* 10^-3 / 2)^2* L * 9.8 = 6.4* 10^-5* i L
i = 171.72 A
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b)
yes, this current is feasible
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Comment before rate in case any doubt, will reply for sure.. goodluck
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