Question

a) Suppose a straight 1.40 mm -diameter copper wire could just "float" horizontally in air because of the force due to the Earth's magnetic field B⃗, which is horizontal, perpendicular to the wire, and of magnitude 3.4×10⁻⁵ T . What current would the wire carry? Does the answer seem feasible? Explain why.

b) The force on a wire carrying 7.95 A is a maximum of 2.13 N when placed between the pole faces of a magnet If the pole faces are 52.5 cm in diameter, what is the approximate strength of the magnetic field?.

Answer 1

21 we have the magnelio field B 2 Guren IN AT 12? This io low amount of current due to No 210 rating 8= 1.40 m. then from 0 Үjo 7 I = 0.085 A 3-4X107 107 2182 1.40 x 103 4IX10 -3.400 3.4 x 10' 41 2 I = 0.34 lytt field, senall megnetic b) We hane - I lB. Giren, Fn = 2.13N 2 2 52.5x102 B 27 I27.95 A Fm 2 B 2 1-2 2-12X102 T 52.5x t. 95 A B = 0.51T