Question

Chapter nu homeWo Dugu wa TZU TUN M - Due Date. JU LULU TIJ (20%) Problem 3: Consider 3 resistors with resistances 1.2 x 1020, 2.6 k2, and 3.6 k 2. 50% Part (a) What would be their resistance, Ry, in kilohms, if they were connected in series? 50% Part (b) What would be their resistance, Rp, in ohms, if they were connected in parallel? Rp = 8 9 sin() coso tan colano asino acoso atano) acotano sinh cosho tanho cotanh Degrees Radians 23 0 Submit I give up! Hints deduction per hint. Hints remaining: Feedback: deduction per feedback

Answer 1

Let R₁=1.2$\times$10² ohm ,R₂=2.6k ohm=2.6$\times$10³ ohm R₃=3.6k ohm=3.6$\times$10³ ohm

Part a.

If R₁ , R₂​​​​​​​ and R₃​​​​​​​ connected in series then

R_s=R₁+R₂​​​​​​​ +R₃​​​​​​​=1.2$\times$10²+2.6$\times$10³+3.6$\times$10³=6.32 kilo -ohm

Part b.

If R₁ , R₂​​​​​​​ and R₃​​​​​​​ connected in parallel then

1/R_s=1/R₁+1/R₂​​​​​​​ +1/R₃​​​​​​​=1/1.2$\times$10²+1/2.6$\times$10³+1/3.6$\times$10³=0.11 kilo -ohm